What is the answer to (x-2)/2+(x-3)/3+(x-4)/4 =10 ?

The answer to (x-2)/2+(x-3)/3+(x-4)/4 =10 is x=12

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(x-2)/2+(x-3)/3+(x-4)/4 =10

\frac{x - 2}{2} + \frac{x - 3}{3} + \frac{x - 4}{4} = 10

x = 12

Solution steps

\frac{x - 2}{2} + \frac{x - 3}{3} + \frac{x - 4}{4} = 10

Multiply by LCM

6 (x - 2) + 4 (x - 3) + 3 (x - 4) = 120

Expand

6 (x - 2) + 4 (x - 3) + 3 (x - 4) : 13 x - 36

13 x - 36 = 120

Move

36

to the right side

13 x = 156

Divide both sides by

13

x = 12

6.3 (2 y) + 9.6 y = 637.5

x^{2} + 7 x y - 44 y^{2}

\frac{16}{x} < x

n - 4 < 5

4 x^{2} + 4 = 8 x

What is the answer to (x-2)/2+(x-3)/3+(x-4)/4 =10 ?
The answer to (x-2)/2+(x-3)/3+(x-4)/4 =10 is x=12
Solve for x: (x-2)/2+(x-3)/3+(x-4)/4 =10
The solution is x=12