What are the solutions to the equation 2x^2+2x+20=0 ?

The solutions to the equation 2x^2+2x+20=0 are x=-1/2+i(sqrt(39))/2 ,x=-1/2-i(sqrt(39))/2

Find the zeros of 2x^2+2x+20=0

The zeros of 2x^2+2x+20=0 are x=-1/2+i(sqrt(39))/2 ,x=-1/2-i(sqrt(39))/2

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2 x^{2} + 2 x + 20 = 0

x = - \frac{1}{2} + i \frac{39}{2}, x = - \frac{1}{2} - i \frac{39}{2}

Solution steps

2 x^{2} + 2 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

Simplify

2^{2} - 4 \cdot 2 \cdot 20 : 239 i

x_{1, 2} = \frac{- 2 \pm 2 39 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2 39 i}{2 \cdot 2}, x_{2} = \frac{- 2 - 2 39 i}{2 \cdot 2}

x = \frac{- 2 + 2 39 i}{2 \cdot 2} : - \frac{1}{2} + i \frac{39}{2}

x = \frac{- 2 - 2 39 i}{2 \cdot 2} : - \frac{1}{2} - i \frac{39}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{39}{2}, x = - \frac{1}{2} - i \frac{39}{2}

- 0.05518 (40) = ln \frac{N}{500}

4 m p + 6 + 3 p + 8 m

- 5 (2 x + 1) = 45

\frac{23 π}{6} \cdot \frac{180}{π}

5 + x^{2} = 2 x^{2} + 13

What are the solutions to the equation 2x^2+2x+20=0 ?
The solutions to the equation 2x^2+2x+20=0 are x=-1/2+i(sqrt(39))/2 ,x=-1/2-i(sqrt(39))/2
Find the zeros of 2x^2+2x+20=0
The zeros of 2x^2+2x+20=0 are x=-1/2+i(sqrt(39))/2 ,x=-1/2-i(sqrt(39))/2