What are the solutions to the equation x^2-8x-65=0 ?

The solutions to the equation x^2-8x-65=0 are x=13,x=-5

Find the zeros of x^2-8x-65=0

The zeros of x^2-8x-65=0 are x=13,x=-5

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x^{2} - 8 x - 65 = 0

x = 13, x = - 5

Solution steps

x^{2} - 8 x - 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 65 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 65) = 18

x_{1, 2} = \frac{- ( - 8 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 18}{2 \cdot 1}

x = \frac{- ( - 8 ) + 18}{2 \cdot 1} : 13

x = \frac{- ( - 8 ) - 18}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 13, x = - 5

25 x^{2} + 80 x + 64 = 0

2 x^{2} + 12 x = 4 - x^{2}

3 x^{2} + 4 x + 6 = 0

4 m^{2} - 3 m^{6} + 5 m^{4}

(\frac{1}{16})^{x} - (\frac{1}{4})^{x} \geq 0

What are the solutions to the equation x^2-8x-65=0 ?
The solutions to the equation x^2-8x-65=0 are x=13,x=-5
Find the zeros of x^2-8x-65=0
The zeros of x^2-8x-65=0 are x=13,x=-5