What are the solutions to the equation 162x^2-180x+54=0 ?

The solutions to the equation 162x^2-180x+54=0 are x= 5/9+i(sqrt(2))/9 ,x= 5/9-i(sqrt(2))/9

Find the zeros of 162x^2-180x+54=0

The zeros of 162x^2-180x+54=0 are x= 5/9+i(sqrt(2))/9 ,x= 5/9-i(sqrt(2))/9

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162 x^{2} - 180 x + 54 = 0

x = \frac{5}{9} + i \frac{2}{9}, x = \frac{5}{9} - i \frac{2}{9}

Solution steps

162 x^{2} - 180 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 180 ) \pm ( - 180 ) ^{2} - 4 \cdot 162 \cdot 54}{2 \cdot 162}

Simplify

(- 180)^{2} - 4 \cdot 162 \cdot 54 : 362 i

x_{1, 2} = \frac{- ( - 180 ) \pm 36 2 i}{2 \cdot 162}

Separate the solutions

x_{1} = \frac{- ( - 180 ) + 36 2 i}{2 \cdot 162}, x_{2} = \frac{- ( - 180 ) - 36 2 i}{2 \cdot 162}

x = \frac{- ( - 180 ) + 36 2 i}{2 \cdot 162} : \frac{5}{9} + i \frac{2}{9}

x = \frac{- ( - 180 ) - 36 2 i}{2 \cdot 162} : \frac{5}{9} - i \frac{2}{9}

The solutions to the quadratic equation are:

x = \frac{5}{9} + i \frac{2}{9}, x = \frac{5}{9} - i \frac{2}{9}

8 m^{2} - 30 m - 27

(m^{\frac{2}{3}} n^{- \frac{1}{3}})^{6}

6 w^{2} - 28 w + 32

35 \cdot 8

lo g_{4} (100)

What are the solutions to the equation 162x^2-180x+54=0 ?
The solutions to the equation 162x^2-180x+54=0 are x= 5/9+i(sqrt(2))/9 ,x= 5/9-i(sqrt(2))/9
Find the zeros of 162x^2-180x+54=0
The zeros of 162x^2-180x+54=0 are x= 5/9+i(sqrt(2))/9 ,x= 5/9-i(sqrt(2))/9