What are the solutions to the equation (2x-1)(x+4)=0 ?

The solutions to the equation (2x-1)(x+4)=0 are x= 1/2 ,x=-4

Find the zeros of (2x-1)(x+4)=0

The zeros of (2x-1)(x+4)=0 are x= 1/2 ,x=-4

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(2 x - 1) (x + 4) = 0

x = \frac{1}{2}, x = - 4

Solution steps

(2 x - 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 4 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 4

7 k^{3} + 7 k^{2} + 9 k + 9

(0.03)^{2}

30 \div 5 (7 - 5) + 3 (- 8 + 2 \cdot 4)

3 (3 n + 2) = 6 (8 n + 1) + 3

9 x + a y + 9 y + a x

What are the solutions to the equation (2x-1)(x+4)=0 ?
The solutions to the equation (2x-1)(x+4)=0 are x= 1/2 ,x=-4
Find the zeros of (2x-1)(x+4)=0
The zeros of (2x-1)(x+4)=0 are x= 1/2 ,x=-4