What is the sum from n=0 to infinity of (3/7)^n ?

The sum from n=0 to infinity of (3/7)^n is 7/4

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sum from n=0 to infinity of (3/7)^n

n = 0 \sum \infty (\frac{3}{7})^{n}

\frac{7}{4}

Solution steps

n = 0 \sum \infty (\frac{3}{7})^{n}

Apply Series Geometric Test:

\frac{7}{4}

= \frac{7}{4}

\frac{d y}{d x} = 9 x^{3}

\frac{d}{d x} (cot (π) x \cdot sec (π) x)

5 x + 6

f (x) = ln (x + x^{2} - 12)

y = \frac{- 2 x}{( x ^{2} + 1 )}

What is the sum from n=0 to infinity of (3/7)^n ?
The sum from n=0 to infinity of (3/7)^n is 7/4