What is (\partial)/(\partial x)(-xyz^2+1) ?

The answer to (\partial)/(\partial x)(-xyz^2+1) is -yz^2

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(\partial)/(\partial x)(-xyz^2+1)

\frac{\partial}{\partial x} (- x y z^{2} + 1)

- y z^{2}

Solution steps

\frac{\partial}{\partial x} (- x y z^{2} + 1)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x y z^{2}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x y z^{2}) = y z^{2}

\frac{\partial}{\partial x} (1) = 0

= - y z^{2} + 0

Simplify

= - y z^{2}

f (x) = - e^{x} x + 3 e^{x}

\int \frac{- 1}{4} e^{- 4 x} 3 x^{2} d x

\int 15 (x + 2)^{4} d x

y^{^{'}} = y (1 - y), y (0) = - 5

n = 0 \sum \infty \frac{1}{( 1 + n ) ^{2}}

What is (\partial)/(\partial x)(-xyz^2+1) ?
The answer to (\partial)/(\partial x)(-xyz^2+1) is -yz^2