What is implicit (dy)/(dx),4y^2-5y+8=2x^2-3x ?

The answer to implicit (dy)/(dx),4y^2-5y+8=2x^2-3x is (dy)/(dx)=(4x-3)/(8y-5)

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implicit (dy)/(dx),4y^2-5y+8=2x^2-3x

implicit derivative

\frac{d y}{d x}, 4 y^{2} - 5 y + 8 = 2 x^{2} - 3 x

\frac{d y}{d x} = \frac{4 x - 3}{8 y - 5}

Solution steps

4 y^{2} - 5 y + 8 = 2 x^{2} - 3 x

Treat

y

y (x)

Differentiate both sides:

8 y \frac{d y}{d x} - 5 \frac{d y}{d x} = 4 x - 3

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{4 x - 3}{8 y - 5}

\frac{d y}{d x} = \frac{4 x - 3}{8 y - 5}

\int 2 x (1 + x^{2})^{2} d x

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 e^{2 x}

\frac{d}{d x} (5 e^{- x} + e^{3 x})

\frac{d}{d x} (ln (\frac{x}{1 + x ^{2}}))

\int \frac{2 x}{( 1 + x ^{2} ) ^{2}} d x

What is implicit (dy)/(dx),4y^2-5y+8=2x^2-3x ?
The answer to implicit (dy)/(dx),4y^2-5y+8=2x^2-3x is (dy)/(dx)=(4x-3)/(8y-5)