What is (\partial)/(\partial x)(bxe^{2xy}) ?

The answer to (\partial)/(\partial x)(bxe^{2xy}) is b(e^{2xy}+2e^{2xy}xy)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(bxe^{2xy})

\frac{\partial}{\partial x} (b x e^{2 x y})

b (e^{2 x y} + 2 e^{2 x y} x y)

Solution steps

\frac{\partial}{\partial x} (b x e^{2 x y})

Treat

b, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{\partial}{\partial x} (x e^{2 x y})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{2 x y}

= b (\frac{\partial}{\partial x} (x) e^{2 x y} + \frac{\partial}{\partial x} (e^{2 x y}) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (e^{2 x y}) = e^{2 x y} \cdot 2 y

= b (1 \cdot e^{2 x y} + e^{2 x y} \cdot 2 y x)

Simplify

= b (e^{2 x y} + 2 e^{2 x y} x y)

\int 4 x^{2} + 9 x^{4} d x

\frac{d}{d x} (1 0^{n x})

f (x) = \frac{14}{( x + 4 ) ^{3}}

\frac{d y}{d x} = \frac{cos ( x )}{y}

n = 1 \sum \infty \frac{5 n}{2 n - 1}

What is (\partial)/(\partial x)(bxe^{2xy}) ?
The answer to (\partial)/(\partial x)(bxe^{2xy}) is b(e^{2xy}+2e^{2xy}xy)