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Popular >

y^'+ycos(x)=0

Solution

y^{^{'}} + y cos (x) = 0

Solution

y = e^{- s i n (x) + c_{1}}

Solution steps

y^{'} (x) + y cos (x) = 0

Solve separable ODE:

y = e^{- s i n (x) + c_{1}}

y = e^{- s i n (x) + c_{1}}

Popular Examples

taylor sqrt(x+1)taylor

x + 1

integral from 1 to 2 of (x^2+8)/(3x-x^2)

\int_{1}^{2} \frac{x ^{2} + 8}{3 x - x ^{2}} d x

derivative of (x^2/(sqrt(x^2-1)))

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 1})

derivative of (7+2x)/(5-8x)derivative of

\frac{7 + 2 x}{5 - 8 x}

(\partial)/(\partial x)(1/(tan(xy)))

\frac{\partial}{\partial x} (\frac{1}{tan ( x y )})

Frequently Asked Questions (FAQ)

What is the solution for y^'+ycos(x)=0 ?
The solution for y^'+ycos(x)=0 is y=e^{-sin(x)+c_{1}}