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Popular >

-2y^'+6x^2=0

Solution

- 2 y^{^{'}} + 6 x^{2} = 0

Solution

y = x^{3} + c_{1}

Solution steps

- 2 y^{'} (x) + 6 x^{2} = 0

Isolate

y^{'} (x) : y^{'} (x) = 3 x^{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 3 x^{2} d x

\int 3 x^{2} d x = x^{3} + c_{1}

y = x^{3} + c_{1}

Popular Examples

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\int \frac{- x ^{2} + x + 4}{x ( x - 2 ) ^{2}} d x

sum from n=1 to infinity of ln((n+1)/n)

n = 1 \sum \infty ln (\frac{n + 1}{n})

9y^{''}-y=(xex)/3

9 y^{^{''}} - y = \frac{x e x}{3}

integral of sin(x)x

\int sin (x) x d x

integral from 3 to 8 of x^3ln(3x)

\int_{3}^{8} x^{3} ln (3 x) d x

Frequently Asked Questions (FAQ)

What is the solution for -2y^'+6x^2=0 ?
The solution for -2y^'+6x^2=0 is y=x^3+c_{1}