What is the integral from 0 to 8 of xe^{-x} ?

The integral from 0 to 8 of xe^{-x} is -9/(e^8)+1

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integral from 0 to 8 of xe^{-x}

\int_{0}^{8} x e^{- x} d x

- \frac{9}{e ^{8}} + 1

Decimal Notation

0.99698 \dots

Solution steps

\int_{0}^{8} x e^{- x} d x

Apply Integration By Parts

: [- e^{- x} x - \int - e^{- x} d x]_{0}^{8}

= [- e^{- x} x - \int - e^{- x} d x]_{0}^{8}

\int - e^{- x} d x = e^{- x}

= [- e^{- x} x - e^{- x}]_{0}^{8}

Compute the boundaries:

- \frac{9}{e ^{8}} + 1

= - \frac{9}{e ^{8}} + 1

\frac{d}{d x} (- \frac{x}{x ^{2} + y ^{2}})

\int \frac{1}{2 - 3 x ^{2}} d x

x \to π - lim (cot (x))

8 e^{4 x}

x y - 5 y^{2} = 4

What is the integral from 0 to 8 of xe^{-x} ?
The integral from 0 to 8 of xe^{-x} is -9/(e^8)+1