What is the solution for (dy)/(dx)=x^3+2x+pi ?

The solution for (dy)/(dx)=x^3+2x+pi is y=(x^4)/4+x^2+pix+c_{1}

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(dy)/(dx)=x^3+2x+pi

\frac{d y}{d x} = x^{3} + 2 x + π

y = \frac{x ^{4}}{4} + x^{2} + π x + c_{1}

Solution steps

\frac{d y}{d x} = x^{3} + 2 x + π

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = x^{3} + 2 x + π

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{3} + 2 x + π d x

\int x^{3} + 2 x + π d x = \frac{x ^{4}}{4} + x^{2} + π x + c_{1}

y = \frac{x ^{4}}{4} + x^{2} + π x + c_{1}

\int_{- 1}^{2} (- x^{2} + x + 2) d x

\frac{d}{d x} (tan (x^{3}))

\frac{sin ^{2} ( x )}{cos ^{2} ( x )}

x \to 4 + lim (2 x - 7)

x + \frac{1}{x ^{3}}

What is the solution for (dy)/(dx)=x^3+2x+pi ?
The solution for (dy)/(dx)=x^3+2x+pi is y=(x^4)/4+x^2+pix+c_{1}