What is the derivative of sqrt(r)+\sqrt[7]{r} ?

The derivative of sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}

What is the first derivative of sqrt(r)+\sqrt[7]{r} ?

The first derivative of sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d r} (r) = \frac{1}{2 r}

= \frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

x \to 2 lim (\frac{2 - x}{2 x ^{2} - 4})

y = 9 x^{2}, y = x^{2} + 6

\int cos^{7} (y) d y

\frac{d}{d x} (- 5 cot (x))

\int \frac{y}{( y + 2 ) ( 3 y - 1 )} d y

What is the derivative of sqrt(r)+\sqrt[7]{r} ?
The derivative of sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}
What is the first derivative of sqrt(r)+\sqrt[7]{r} ?
The first derivative of sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}