What is the limit as x approaches (5pi)/6 of cos(x) ?

The limit as x approaches (5pi)/6 of cos(x) is -(sqrt(3))/2

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limit as x approaches (5pi)/6 of cos(x)

x \to \frac{5 π}{6} lim (cos (x))

- \frac{3}{2}

Decimal Notation

- 0.86602 \dots

Solution steps

x \to \frac{5 π}{6} lim (cos (x))

Plug in the value

x = \frac{5 π}{6}

= cos (\frac{5 π}{6})

Use the following trivial identity:

cos (\frac{5 π}{6}) = - \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{3}{2}

\frac{d}{d y} (\frac{x}{y ^{2}})

n = 1 \sum \infty \frac{5}{n ( n + 6 )}

2 x^{2} + 3 x y + 1 y^{3} = - 10, (- 3, - 4)

x^{2} y^{^{''}} + x y^{^{'}} + y = sec (ln (x))

\frac{d}{d x} (\frac{x + 2}{x - 3})

What is the limit as x approaches (5pi)/6 of cos(x) ?
The limit as x approaches (5pi)/6 of cos(x) is -(sqrt(3))/2