What is inverse oflaplace 5 ?

The answer to inverse oflaplace 5 is 5\delta(t)

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inverse oflaplace 5

inverse laplace

5

5 δ (t)

Solution steps

L^{- 1} {5}

= L^{- 1} {5 \cdot 1}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 5 L^{- 1} {1}

Use Inverse Laplace Transform table:

L^{- 1} {1} = δ (t)

Where

δ (t)

is Dirac delta function

= 5 δ (t)

\frac{d}{d x} (9 x - 45)

f (x) = 4 x^{- 3} + x^{2} + 14

\frac{d}{d x} (e^{- \frac{2}{3} x})

\frac{d}{d x} (\frac{x ^{2} - 2 x}{x})

x \to 0 lim (x^{4 s i n (x)})