What is the derivative of (x^2+x^2) ?

The derivative of (x^2+x^2) is 2(x^2+x)(2x+1)

What is the first derivative of (x^2+x^2) ?

The first derivative of (x^2+x^2) is 2(x^2+x)(2x+1)

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\frac{d}{d x} ((x^{2} + x)^{2})

2 (x^{2} + x) (2 x + 1)

Solution steps

\frac{d}{d x} ((x^{2} + x)^{2})

Apply the chain rule:

2 (x^{2} + x) \frac{d}{d x} (x^{2} + x)

= 2 (x^{2} + x) \frac{d}{d x} (x^{2} + x)

\frac{d}{d x} (x^{2} + x) = 2 x + 1

= 2 (x^{2} + x) (2 x + 1)

n = 0 \sum \infty \frac{n ^{5}}{5 ^{n}}

t \to - 1 lim (ln (t + 2))

y = \frac{z ^{2} + 1}{z ^{2} - 1}

x \to - \infty lim (\frac{x - 8}{x ^{2} + 6})

\frac{d}{d x} (\frac{d y}{d x}) + y = - 1

What is the derivative of (x^2+x^2) ?
The derivative of (x^2+x^2) is 2(x^2+x)(2x+1)
What is the first derivative of (x^2+x^2) ?
The first derivative of (x^2+x^2) is 2(x^2+x)(2x+1)