What is (\partial)/(\partial x)(ln(x+z)) ?

The answer to (\partial)/(\partial x)(ln(x+z)) is 1/(x+z)

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(\partial)/(\partial x)(ln(x+z))

\frac{\partial}{\partial x} (ln (x + z))

\frac{1}{x + z}

Solution steps

\frac{\partial}{\partial x} (ln (x + z))

Treat

z

as a constant

Apply the chain rule:

\frac{1}{x + z} \frac{\partial}{\partial x} (x + z)

= \frac{1}{x + z} \frac{\partial}{\partial x} (x + z)

\frac{\partial}{\partial x} (x + z) = 1

= \frac{1}{x + z} \cdot 1

Simplify

= \frac{1}{x + z}

\int 5 sin (6 x) + 6 sin (5 x) d x

\frac{d}{d x} ((x - 2)^{3} (x - 1))

\frac{x - 1}{x + 1}

y = (2 x + 1)^{3} + 6 x (2 x + 1)^{2}

\frac{\partial}{\partial y} (e^{- 3 x} cos (6 y))

What is (\partial)/(\partial x)(ln(x+z)) ?
The answer to (\partial)/(\partial x)(ln(x+z)) is 1/(x+z)