What is the derivative of x^2-8x+12 ?

The derivative of x^2-8x+12 is 2x-8

What is the first derivative of x^2-8x+12 ?

The first derivative of x^2-8x+12 is 2x-8

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\frac{d}{d x} (x^{2} - 8 x + 12)

2 x - 8

Solution steps

\frac{d}{d x} (x^{2} - 8 x + 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (12)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (12) = 0

= 2 x - 8 + 0

Simplify

= 2 x - 8

\int \frac{1}{8 - 3 x} d x

\int_{0}^{1} - ln (x) d x

\frac{d y}{d x} = - y (x + 1)

x + 4 x + 2

x \to 3 lim \frac{\frac{1}{3} x - \frac{1}{3}}{x - 3}

What is the derivative of x^2-8x+12 ?
The derivative of x^2-8x+12 is 2x-8
What is the first derivative of x^2-8x+12 ?
The first derivative of x^2-8x+12 is 2x-8