What is laplacetransform 2-t ?

The answer to laplacetransform 2-t is 2/s-1/(s^2)

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laplacetransform 2-t

laplace transform

2 - t

\frac{2}{s} - \frac{1}{s ^{2}}

Solution steps

L {2 - t}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {2} - L {t}

L {2} : \frac{2}{s}

L {t} : \frac{1}{s ^{2}}

= \frac{2}{s} - \frac{1}{s ^{2}}

(2 x + 5)^{3} (x^{5} + 3)^{6}

\int \frac{16 x}{1 - x ^{4}} d x

\frac{d}{d x} (x^{3} + 5)

\frac{d y}{d x} = 8 x e^{7 y}

\int \frac{- 7}{x ^{2} + 16} d x

What is laplacetransform 2-t ?
The answer to laplacetransform 2-t is 2/s-1/(s^2)