What is the derivative of f(x)=(2x^{3/2}-x^2+4)/x ?

The derivative of f(x)=(2x^{3/2}-x^2+4)/x is (-x^2+x^{3/2}-4)/(x^2)

What is the first derivative of f(x)=(2x^{3/2}-x^2+4)/x ?

The first derivative of f(x)=(2x^{3/2}-x^2+4)/x is (-x^2+x^{3/2}-4)/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{2 x ^{\frac{3}{2}} - x ^{2} + 4}{x}

\frac{- x ^{2} + x ^{\frac{3}{2}} - 4}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{\frac{3}{2}} - x ^{2} + 4}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x ^{\frac{3}{2}} - x ^{2} + 4 ) x - \frac{d x}{d x} ( 2 x ^{\frac{3}{2}} - x ^{2} + 4 )}{x ^{2}}

\frac{d}{d x} (2 x^{\frac{3}{2}} - x^{2} + 4) = - 2 x + 3 x^{\frac{1}{2}}

\frac{d x}{d x} = 1

= \frac{( - 2 x + 3 x ^{\frac{1}{2}} ) x - 1 \cdot ( 2 x ^{\frac{3}{2}} - x ^{2} + 4 )}{x ^{2}}

Simplify

\frac{( - 2 x + 3 x ^{\frac{1}{2}} ) x - 1 \cdot ( 2 x ^{\frac{3}{2}} - x ^{2} + 4 )}{x ^{2}} : \frac{- x ^{2} + x ^{\frac{3}{2}} - 4}{x ^{2}}

= \frac{- x ^{2} + x ^{\frac{3}{2}} - 4}{x ^{2}}

\frac{500}{12 + 5 e ^{- 0.5 t}}

\frac{d y}{d x}, x = y^{3} - 8 y^{2} + 5, (- 2, 1)

\frac{1}{s ^{2} - 2 s - 3}

x \to 0 + lim (\frac{x - [ x ]}{[ x ] - 2 x})

\frac{d}{d x} (x^{2} lo g_{2} (7 - 6 x))

What is the derivative of f(x)=(2x^{3/2}-x^2+4)/x ?
The derivative of f(x)=(2x^{3/2}-x^2+4)/x is (-x^2+x^{3/2}-4)/(x^2)
What is the first derivative of f(x)=(2x^{3/2}-x^2+4)/x ?
The first derivative of f(x)=(2x^{3/2}-x^2+4)/x is (-x^2+x^{3/2}-4)/(x^2)