What is the integral from 0 to 1 of integral from 0 to s^5 of cos(s^6) ?

The integral from 0 to 1 of integral from 0 to s^5 of cos(s^6) is 1/6 sin(1)

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integral from 0 to 1 of integral from 0 to s^5 of cos(s^6)

\int_{0}^{1} \int_{0}^{s^{5}} cos (s^{6}) d t d s

\frac{1}{6} sin (1)

Decimal Notation

0.14024 \dots

Solution steps

\int_{0}^{1} \int_{0}^{s^{5}} cos (s^{6}) d t d s

\int_{0}^{s^{5}} cos (s^{6}) d t = s^{5} cos (s^{6})

= \int_{0}^{1} s^{5} cos (s^{6}) d s

\int_{0}^{1} s^{5} cos (s^{6}) d s = \frac{1}{6} sin (1)

= \frac{1}{6} sin (1)

y^{^{'}} = - t y

y^{^{'}} = \frac{( x + 2 y )}{x}

\frac{d}{d x} ((1 + e^{- x})^{- 1})

\frac{d y}{d x} = y (1 - y)

x \to 4 lim (5 x^{2} - 2 x + 3)

What is the integral from 0 to 1 of integral from 0 to s^5 of cos(s^6) ?
The integral from 0 to 1 of integral from 0 to s^5 of cos(s^6) is 1/6 sin(1)