What is the integral of (10)/(sqrt(1-x^2)) ?

The integral of (10)/(sqrt(1-x^2)) is 10arcsin(x)+C

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integral of (10)/(sqrt(1-x^2))

\int \frac{10}{1 - x ^{2}} d x

10 arcsin (x) + C

Solution steps

\int \frac{10}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 10 arcsin (x)

Add a constant to the solution

= 10 arcsin (x) + C

x y^{^{''}} - 2 y^{^{'}} = 0

\int \frac{6}{( 9 t ^{2} + 1 ) ^{2}} d t

\frac{d}{d x} (A x^{2} e^{x})

\int_{0}^{3} 450.268 e^{1.12567 t} d t

x \to \infty lim (e^{x} - x)

What is the integral of (10)/(sqrt(1-x^2)) ?
The integral of (10)/(sqrt(1-x^2)) is 10arcsin(x)+C