What is inverse oflaplace 6/(s^2) ?

The answer to inverse oflaplace 6/(s^2) is 6t

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inverse oflaplace 6/(s^2)

inverse laplace

\frac{6}{s ^{2}}

6 t

Solution steps

L^{- 1} {\frac{6}{s ^{2}}}

= L^{- 1} {6 \cdot \frac{1}{s ^{2}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 6 L^{- 1} {\frac{1}{s ^{2}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{1}{s ^{2}}} = t

= 6 t

\frac{d x}{d t} = 3 x^{2} + 2 x

\frac{d}{d x} (\frac{arcsin ( x )}{1 - x ^{2}})

x \to 8 - lim (\frac{64 - x ^{2}}{x - 8})

\frac{d}{d x} (x 64 - x^{2})

What is inverse oflaplace 6/(s^2) ?
The answer to inverse oflaplace 6/(s^2) is 6t