What is taylor f(x)=2^x ?

The answer to taylor f(x)=2^x is 1+ln(2)x+(ln^2(2))/2 x^2+(ln^3(2))/6 x^3+(ln^4(2))/(24)x^4+\ldots

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taylor f(x)=2^x

taylor

f (x) = 2^{x}

1 + ln (2) x + \frac{ln ^{2} ( 2 )}{2} x^{2} + \frac{ln ^{3} ( 2 )}{6} x^{3} + \frac{ln ^{4} ( 2 )}{24} x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 1 + \frac{\frac{d}{d x} ( 2 ^{x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 2 ^{x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 2 ^{x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{ln ( 2 )}{1 !} x + \frac{ln ^{2} ( 2 )}{2 !} x^{2} + \frac{ln ^{3} ( 2 )}{3 !} x^{3} + \frac{ln ^{4} ( 2 )}{4 !} x^{4} + \dots

Refine

= 1 + ln (2) x + \frac{ln ^{2} ( 2 )}{2} x^{2} + \frac{ln ^{3} ( 2 )}{6} x^{3} + \frac{ln ^{4} ( 2 )}{24} x^{4} + \dots

x \to - \infty lim (\frac{6}{( 1 + e ^{- x} )})

x \to 7 lim (\frac{x ^{3} - 4 x ^{2} - 19 x - 14}{x ^{2} - 8 x - 7})

y^{^{''}} + 2 y^{^{'}} + y = x^{2} - 2 x + 1

\frac{d}{d x} ((x^{4} ln (x))^{5})

x \to 6 lim (ln (6 - x))

What is taylor f(x)=2^x ?
The answer to taylor f(x)=2^x is 1+ln(2)x+(ln^2(2))/2 x^2+(ln^3(2))/6 x^3+(ln^4(2))/(24)x^4+\ldots