What is the integral of (x^2+1)/(sqrt(x)) ?

The integral of (x^2+1)/(sqrt(x)) is 2/5 x^{5/2}+2sqrt(x)+C

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integral of (x^2+1)/(sqrt(x))

\int \frac{x ^{2} + 1}{x} d x

\frac{2}{5} x^{\frac{5}{2}} + 2 x + C

Solution steps

\int \frac{x ^{2} + 1}{x} d x

Expand

\frac{x ^{2} + 1}{x} : x^{\frac{3}{2}} + \frac{1}{x}

= \int x^{\frac{3}{2}} + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{2}} d x + \int \frac{1}{x} d x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int \frac{1}{x} d x = 2 x

= \frac{2}{5} x^{\frac{5}{2}} + 2 x

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} + 2 x + C

y = - \frac{1}{4} x^{2}, (- 2, - 1)

(1 + 2 x)^{2}

y^{^{''}} - 8 y^{^{'}} + 41 y = 0

\frac{d}{d x} ((x^{2} - x + 1)^{- 7})

\int \frac{x - 1}{x ( x ^{2} - 5 x + 6 )} d x

What is the integral of (x^2+1)/(sqrt(x)) ?
The integral of (x^2+1)/(sqrt(x)) is 2/5 x^{5/2}+2sqrt(x)+C