What is the solution for y^{''}-2y^'-63y=0 ?

The solution for y^{''}-2y^'-63y=0 is y=c_{1}e^{9t}+c_{2}e^{-7t}

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y^{''}-2y^'-63y=0

y^{^{''}} - 2 y^{^{'}} - 63 y = 0

y = c_{1} e^{9 t} + c_{2} e^{- 7 t}

Solution steps

y^{''} (t) - 2 y^{'} (t) - 63 y = 0

Solve linear ODE:

y = c_{1} e^{9 t} + c_{2} e^{- 7 t}

y = c_{1} e^{9 t} + c_{2} e^{- 7 t}

n = 1 \sum \infty \frac{1}{n ^{- 1}}

\frac{d ^{2} y}{d ^{2} x} + \frac{4 d y}{d x} + 3 y = 0

x \to 0 lim (\frac{x}{x ^{2} - 4})

t^{3} \frac{d y}{d t} + 3 t^{2} y = 2 cos (t)

\int x^{15} e^{- x^{16}} d x

What is the solution for y^{''}-2y^'-63y=0 ?
The solution for y^{''}-2y^'-63y=0 is y=c_{1}e^{9t}+c_{2}e^{-7t}