What is the derivative of 9xe^xcsc(x) ?

The derivative of 9xe^xcsc(x) is 9(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))

What is the first derivative of 9xe^xcsc(x) ?

The first derivative of 9xe^xcsc(x) is 9(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

9 x e^{x} csc (x)

9 (e^{x} csc (x) + x (e^{x} csc (x) - e^{x} cot (x) csc (x)))

Solution steps

\frac{d}{d x} (9 x e^{x} csc (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (x e^{x} csc (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x} csc (x)

= 9 (\frac{d x}{d x} e^{x} csc (x) + \frac{d}{d x} (e^{x} csc (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x} csc (x)) = e^{x} csc (x) - e^{x} cot (x) csc (x)

= 9 (1 \cdot e^{x} csc (x) + (e^{x} csc (x) - e^{x} cot (x) csc (x)) x)

Simplify

= 9 (e^{x} csc (x) + x (e^{x} csc (x) - e^{x} cot (x) csc (x)))

\frac{1}{x}, 1, 2

\int \frac{( x ^{2} + 1 )}{( x - 3 ) ( x - 2 ) ^{2}} d x

\frac{d y}{d x}, x y^{3} + 10 y^{11} = 9

y^{2} - 3 x = 1, x - y = 3

\frac{d y}{d t} = - 100 y + 101 cos (t) + 99 sin (t)

What is the derivative of 9xe^xcsc(x) ?
The derivative of 9xe^xcsc(x) is 9(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))
What is the first derivative of 9xe^xcsc(x) ?
The first derivative of 9xe^xcsc(x) is 9(e^xcsc(x)+x(e^xcsc(x)-e^xcot(x)csc(x)))