What is the tangent of f(x)=-1-2cos(x),\at x=-pi/4 ?

The tangent of f(x)=-1-2cos(x),\at x=-pi/4 is y=-sqrt(2)x-1-sqrt(2)-pi/(2sqrt(2))

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tangent of f(x)=-1-2cos(x),\at x=-pi/4

tangent of

f (x) = - 1 - 2 cos (x), at x = - \frac{π}{4}

y = - 2 x - 1 - 2 - \frac{π}{2 2}

Solution steps

Find the tangent point:

(- \frac{π}{4}, - 1 - 2)

Find the slope of

f (x) = - 1 - 2 cos (x) : \frac{df ( x )}{d x} = 2 sin (x)

Compute the slope of

f (x) = - 1 - 2 cos (x)

x = - \frac{π}{4} : m = - 2

Find the line with slope m=

- 2

and passing through

(- \frac{π}{4}, - 1 - 2) : y = - 2 x - 1 - 2 - \frac{π}{2 2}

y = - 2 x - 1 - 2 - \frac{π}{2 2}

y^{^{'}} = (x - 3) (y + 1)^{\frac{2}{3}}, y (0) = - 1

\frac{d}{d x} (\frac{2 x + 3}{3 x ^{2} - 4})

(5 x - 4)^{4}, at x = 2

\int_{0}^{1} e^{- x} d x

\int 2 x x^{2} + 3 d x

What is the tangent of f(x)=-1-2cos(x),\at x=-pi/4 ?
The tangent of f(x)=-1-2cos(x),\at x=-pi/4 is y=-sqrt(2)x-1-sqrt(2)-pi/(2sqrt(2))