What is the d/(dt)(\sqrt[7]{t}+6sqrt(t^7)) ?

The d/(dt)(\sqrt[7]{t}+6sqrt(t^7)) is (1+147t^{47/14})/(7t^{6/7)}

What is the first d/(dt)(\sqrt[7]{t}+6sqrt(t^7)) ?

The first d/(dt)(\sqrt[7]{t}+6sqrt(t^7)) is (1+147t^{47/14})/(7t^{6/7)}

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\frac{1 + 147 t ^{\frac{47}{14}}}{7 t ^{\frac{6}{7}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (6 t^{7}) = 21 t^{\frac{5}{2}}

= \frac{1}{7 t ^{\frac{6}{7}}} + 21 t^{\frac{5}{2}}

Simplify

\frac{1}{7 t ^{\frac{6}{7}}} + 21 t^{\frac{5}{2}} : \frac{1 + 147 t ^{\frac{47}{14}}}{7 t ^{\frac{6}{7}}}

= \frac{1 + 147 t ^{\frac{47}{14}}}{7 t ^{\frac{6}{7}}}

\int \frac{1}{( 2 x - 1 ) ( x + 3 )} d x

\frac{\partial}{\partial x} (3 sin (3 x))

\int sin^{6} (\frac{x}{2}) d x

\frac{d y}{d x} - 3 y = 6

f (t) = 16 t^{2}

What is the d/(dt)(\sqrt[7]{t}+6sqrt(t^7)) ?
The d/(dt)(\sqrt[7]{t}+6sqrt(t^7)) is (1+147t^{47/14})/(7t^{6/7)}
What is the first d/(dt)(\sqrt[7]{t}+6sqrt(t^7)) ?
The first d/(dt)(\sqrt[7]{t}+6sqrt(t^7)) is (1+147t^{47/14})/(7t^{6/7)}