What is the derivative of sqrt(9x+8) ?

The derivative of sqrt(9x+8) is 9/(2sqrt(9x+8))

What is the first derivative of sqrt(9x+8) ?

The first derivative of sqrt(9x+8) is 9/(2sqrt(9x+8))

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\frac{d}{d x} (9 x + 8)

\frac{9}{2 9 x + 8}

Solution steps

\frac{d}{d x} (9 x + 8)

Apply the chain rule:

\frac{1}{2 9 x + 8} \frac{d}{d x} (9 x + 8)

= \frac{1}{2 9 x + 8} \frac{d}{d x} (9 x + 8)

\frac{d}{d x} (9 x + 8) = 9

= \frac{1}{2 9 x + 8} \cdot 9

Simplify

\frac{1}{2 9 x + 8} \cdot 9 : \frac{9}{2 9 x + 8}

= \frac{9}{2 9 x + 8}

\int \frac{tan ( x )}{sec ( x ) + 4 cos ( x )} d x

\int 12 x + 5 d x

\frac{\partial}{\partial x} (cos (4 y^{2} - 2 x))

\frac{d}{d x} (sin (x^{t a n (x)}))

(2 x + 1) y^{^{'}} + 2 y = 4 x, y (0) = 1

What is the derivative of sqrt(9x+8) ?
The derivative of sqrt(9x+8) is 9/(2sqrt(9x+8))
What is the first derivative of sqrt(9x+8) ?
The first derivative of sqrt(9x+8) is 9/(2sqrt(9x+8))