What is the derivative of 1-2sin^3(x) ?

The derivative of 1-2sin^3(x) is -6sin^2(x)cos(x)

What is the first derivative of 1-2sin^3(x) ?

The first derivative of 1-2sin^3(x) is -6sin^2(x)cos(x)

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derivative of

1 - 2 sin^{3} (x)

- 6 sin^{2} (x) cos (x)

Solution steps

\frac{d}{d x} (1 - 2 sin^{3} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (2 sin^{3} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 sin^{3} (x)) = 6 sin^{2} (x) cos (x)

= 0 - 6 sin^{2} (x) cos (x)

Simplify

= - 6 sin^{2} (x) cos (x)

\int \frac{x ^{3}}{e ^{x}} d x

\frac{d}{d x} (\frac{4 x ^{5} + 6}{x ^{3}})

- \frac{5}{x}

x, x^{2}, [0, 1]

x \to \infty lim (x \cdot 3)

What is the derivative of 1-2sin^3(x) ?
The derivative of 1-2sin^3(x) is -6sin^2(x)cos(x)
What is the first derivative of 1-2sin^3(x) ?
The first derivative of 1-2sin^3(x) is -6sin^2(x)cos(x)