What is area-cos(x),cos^2(x),[(-pi)/2 , pi/2 ] ?

The answer to area-cos(x),cos^2(x),[(-pi)/2 , pi/2 ] is 2+pi/2

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area-cos(x),cos^2(x),[(-pi)/2 , pi/2 ]

area

- cos (x), cos^{2} (x), [\frac{- π}{2}, \frac{π}{2}]

2 + \frac{π}{2}

Decimal Notation

3.57079 \dots

Solution steps

Apply the area formula:

\int_{\frac{- π}{2}}^{\frac{π}{2}} cos (x) + cos^{2} (x) d x

Solve

\int_{\frac{- π}{2}}^{\frac{π}{2}} cos (x) + cos^{2} (x) d x : 2 + \frac{π}{2}

The area is:

= 2 + \frac{π}{2}

\int 12 x d x

\int \frac{3}{t} d t

x \to 8 lim (\frac{x}{ln ( 9 - x )})

x \to 5 lim (\frac{2}{x + 5})

2 \frac{d y}{d x} = 2 x - y

What is area-cos(x),cos^2(x),[(-pi)/2 , pi/2 ] ?
The answer to area-cos(x),cos^2(x),[(-pi)/2 , pi/2 ] is 2+pi/2