What is the derivative of 1/(3-2x) ?

The derivative of 1/(3-2x) is 2/((3-2x)^2)

What is the first derivative of 1/(3-2x) ?

The first derivative of 1/(3-2x) is 2/((3-2x)^2)

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derivative of

\frac{1}{3 - 2 x}

\frac{2}{( 3 - 2 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{3 - 2 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((3 - 2 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 - 2 x ) ^{2}} \frac{d}{d x} (3 - 2 x)

= - \frac{1}{( 3 - 2 x ) ^{2}} \frac{d}{d x} (3 - 2 x)

\frac{d}{d x} (3 - 2 x) = - 2

= - \frac{1}{( 3 - 2 x ) ^{2}} (- 2)

Simplify

- \frac{1}{( 3 - 2 x ) ^{2}} (- 2) : \frac{2}{( 3 - 2 x ) ^{2}}

= \frac{2}{( 3 - 2 x ) ^{2}}

\int \frac{1}{( x ^{2} - 4 ) ^{\frac{1}{2}}} d x

(1 + e^{x}) y y^{^{'}} = e^{x}, y (0) = 1

f (x) = 3 x^{2} - 8 x - x

x \to - 3 lim (x^{3} - 4 x^{2} - 7)

n = 1 \sum \infty \frac{n - 9}{n + 9}

What is the derivative of 1/(3-2x) ?
The derivative of 1/(3-2x) is 2/((3-2x)^2)
What is the first derivative of 1/(3-2x) ?
The first derivative of 1/(3-2x) is 2/((3-2x)^2)