What is the tangent of 3x^2+7x-4 ?

The tangent of 3x^2+7x-4 is y=(6a_{0}+7)x-3a_{0}^2-4

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tangent of 3x^2+7x-4

tangent of

3 x^{2} + 7 x - 4

y = (6 a_{0} + 7) x - 3 a_{0}^{2} - 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} + 7 a_{0} - 4)

Find the slope of

y = 3 x^{2} + 7 x - 4 : \frac{d y}{d x} = 6 x + 7

Compute the slope of

y = 3 x^{2} + 7 x - 4

x = a_{0} : m = 6 a_{0} + 7

Find the line with slope m=

6 a_{0} + 7

and passing through

(a_{0}, 3 a_{0}^{2} + 7 a_{0} - 4) : y = (6 a_{0} + 7) x - 3 a_{0}^{2} - 4

y = (6 a_{0} + 7) x - 3 a_{0}^{2} - 4

1 - 289 x^{2} arccos (17 x)

h \to 0 lim \frac{( ( \frac{1}{1 - ( x + h )} ) - ( \frac{1}{1 - x} ) )}{h}

\frac{d}{d x} (\frac{1}{( x + y )})

x \to + 0 + lim ((1 + x)^{(\frac{1}{x})})

\frac{d y}{d x} = 1 + y - x

What is the tangent of 3x^2+7x-4 ?
The tangent of 3x^2+7x-4 is y=(6a_{0}+7)x-3a_{0}^2-4