What is the tangent of 3x^2-6x-9,\at x=3 ?

The tangent of 3x^2-6x-9,\at x=3 is y=12x-36

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tangent of 3x^2-6x-9,\at x=3

tangent of

3 x^{2} - 6 x - 9, at x = 3

y = 12 x - 36

Solution steps

Find the tangent point:

(3, 0)

Find the slope of

y = 3 x^{2} - 6 x - 9 : \frac{d y}{d x} = 6 x - 6

Compute the slope of

y = 3 x^{2} - 6 x - 9

x = 3 : m = 12

Find the line with slope m=

12

and passing through

(3, 0) : y = 12 x - 36

y = 12 x - 36

\frac{\partial}{\partial y} (\frac{x y ^{2}}{x ^{2} y ^{3} + 1})

x \to 1 lim (\frac{x + 3}{x - 2})

6, 0, 16 - 2 x

\frac{d y}{d x} = \frac{x y}{3}

\frac{d}{d x} (x^{- 2} \cdot ln (x))

What is the tangent of 3x^2-6x-9,\at x=3 ?
The tangent of 3x^2-6x-9,\at x=3 is y=12x-36