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Popular >

ty^'-y=t^2e^{-t}

Solution

t y^{^{'}} - y = t^{2} e^{- t}

Solution

y = - e^{- t} t + c_{1} t

Solution steps

t y^{'} (t) - y = t^{2} e^{- t}

Solve linear ODE:

y = - e^{- t} t + c_{1} t

y = - e^{- t} t + c_{1} t

Popular Examples

integral of (-1+x)/(x^2)

\int \frac{- 1 + x}{x ^{2}} d x

(\partial)/(\partial x)(3x^2y^4-4)

\frac{\partial}{\partial x} (3 x^{2} y^{4} - 4)

integral of 1/(sin(x)+cos(x))

\int \frac{1}{sin ( x ) + cos ( x )} d x

integral from-1 to 1 of 1/(2x+3)

\int_{- 1}^{1} \frac{1}{2 x + 3} d x

derivative of 1/3 x^{(1/2}-x^{(3/2)})

\frac{d}{d x} (\frac{1}{3} x^{(\frac{1}{2})} - x^{(\frac{3}{2})})

Frequently Asked Questions (FAQ)

What is the solution for ty^'-y=t^2e^{-t} ?
The solution for ty^'-y=t^2e^{-t} is y=-e^{-t}t+c_{1}t