What is the derivative of f(x)=(x^2+5)^9 ?

The derivative of f(x)=(x^2+5)^9 is 18x(x^2+5)^8

What is the first derivative of f(x)=(x^2+5)^9 ?

The first derivative of f(x)=(x^2+5)^9 is 18x(x^2+5)^8

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derivative of

f (x) = (x^{2} + 5)^{9}

18 x (x^{2} + 5)^{8}

Solution steps

\frac{d}{d x} ((x^{2} + 5)^{9})

Apply the chain rule:

9 (x^{2} + 5)^{8} \frac{d}{d x} (x^{2} + 5)

= 9 (x^{2} + 5)^{8} \frac{d}{d x} (x^{2} + 5)

\frac{d}{d x} (x^{2} + 5) = 2 x

= 9 (x^{2} + 5)^{8} \cdot 2 x

Simplify

= 18 x (x^{2} + 5)^{8}

\int t^{3} e^{t^{2}} d t

\frac{d}{d x} (2 + x)

\frac{d y}{d x}, 15 x = 15 y + 5 y^{3} + 3 y^{5}

y^{^{'}} + \frac{y}{x} = 5 \cdot x^{3}

\frac{d}{d x} (e^{- 2 x} \cdot sin (x))

What is the derivative of f(x)=(x^2+5)^9 ?
The derivative of f(x)=(x^2+5)^9 is 18x(x^2+5)^8
What is the first derivative of f(x)=(x^2+5)^9 ?
The first derivative of f(x)=(x^2+5)^9 is 18x(x^2+5)^8