What is the derivative of (925+20x-0.079x^2)/(484) ?

The derivative of (925+20x-0.079x^2)/(484) is 0.00206…(-0.158x+20)

What is the first derivative of (925+20x-0.079x^2)/(484) ?

The first derivative of (925+20x-0.079x^2)/(484) is 0.00206…(-0.158x+20)

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derivative of

\frac{925 + 20 x - 0.079 x ^{2}}{484}

0.00206 \dots (- 0.158 x + 20)

Solution steps

\frac{d}{d x} (\frac{925 + 20 x - 0.079 x ^{2}}{484})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{484} \frac{d}{d x} (925 + 20 x - 0.079 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{484} (\frac{d}{d x} (925) + \frac{d}{d x} (20 x) - \frac{d}{d x} (0.079 x^{2}))

\frac{d}{d x} (925) = 0

\frac{d}{d x} (20 x) = 20

\frac{d}{d x} (0.079 x^{2}) = 0.158 x

= \frac{1}{484} (0 + 20 - 0.158 x)

Simplify

= 0.00206 \dots (- 0.158 x + 20)

\frac{d}{d x} (\frac{csc ^{2} ( x ) - cot ^{3} ( x )}{tan ( x ^{2} + 2 x )})

\int x \cdot lo g_{e} (x) d x

\int_{9}^{24} (- x + 12) d x

ln (s)

y^{^{'}} = \frac{3 y ^{2} + 4 x}{2 x y}

What is the derivative of (925+20x-0.079x^2)/(484) ?
The derivative of (925+20x-0.079x^2)/(484) is 0.00206…(-0.158x+20)
What is the first derivative of (925+20x-0.079x^2)/(484) ?
The first derivative of (925+20x-0.079x^2)/(484) is 0.00206…(-0.158x+20)