What is the integral of 1/(p^2+1) ?

The integral of 1/(p^2+1) is arctan(p)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(p^2+1)

\int \frac{1}{p ^{2} + 1} d p

arctan (p) + C

Solution steps

\int \frac{1}{p ^{2} + 1} d p

Use the common integral:

\int \frac{1}{p ^{2} + 1} d p = arctan (p)

= arctan (p)

Add a constant to the solution

= arctan (p) + C

\frac{d}{d x} (x e^{y} + y^{2} e^{x} - \frac{1}{3} x + 4)

\int x e^{3 x^{2}} d x

\frac{d}{d x} (e^{i x})

\int \frac{2 cos ( ln ( x ) )}{x} d x

\frac{\partial}{\partial y} (e^{x^{y}})