What is (\partial ^2)/(\partial x\partial y)((xy)/(x-y)) ?

The answer to (\partial ^2)/(\partial x\partial y)((xy)/(x-y)) is -(2xy)/((x-y)^3)

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(\partial ^2)/(\partial x\partial y)((xy)/(x-y))

\frac{\partial ^{2}}{\partial x \partial y} (\frac{x y}{x - y})

- \frac{2 x y}{( x - y ) ^{3}}

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} (\frac{x y}{x - y})

\frac{\partial}{\partial x} (\frac{x y}{x - y}) = - \frac{y ^{2}}{( x - y ) ^{2}}

= \frac{\partial}{\partial y} (- \frac{y ^{2}}{( x - y ) ^{2}})

\frac{\partial}{\partial y} (- \frac{y ^{2}}{( x - y ) ^{2}}) = - \frac{2 x y}{( x - y ) ^{3}}

= - \frac{2 x y}{( x - y ) ^{3}}

x \to + 0 lim (x^{4} cos (\frac{π}{x}))

f (x) = \frac{e ^{x}}{2 + 4 x}

f (x) = - 2 sin (2 x)

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\int x^{3} (ln (x))^{2} d x

What is (\partial ^2)/(\partial x\partial y)((xy)/(x-y)) ?
The answer to (\partial ^2)/(\partial x\partial y)((xy)/(x-y)) is -(2xy)/((x-y)^3)