What is the first derivative of 3x+6 ?

The first derivative of 3x+6 is 3

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derivative of 3x+6

\frac{d}{d x} (3 x + 6)

3

Solution steps

\frac{d}{d x} (3 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (6)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (6) = 0

= 3 + 0

Simplify

= 3

y^{^{'}} - 3 y = 6

f (x) = cos (sin (x^{2}))

\int (x + 1)^{- 3} d x

\int \frac{x ^{2}}{x ^{3} - 2} d x

\frac{d y}{d x} = \frac{( 1 + x )}{x y ^{2}}, y (1) = 2