What is the derivative of 5^{x,x} ?

The derivative of 5^{x,x} is e^{(x,x)ln(5)}ln(5)(,(1*x+1*x))

What is the first derivative of 5^{x,x} ?

The first derivative of 5^{x,x} is e^{(x,x)ln(5)}ln(5)(,(1*x+1*x))

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\frac{d}{d x} (5^{x, x})

e^{(x, x) l n (5)} ln (5) (, (1 \cdot x + 1 \cdot x))

Solution steps

\frac{d}{d x} (5^{x, x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

5^{x, x} = e^{(x, x) l n (5)}

= \frac{d}{d x} (e^{(x, x) l n (5)})

Apply the chain rule:

e^{(x, x) l n (5)} \frac{d}{d x} ((x, x) ln (5))

= e^{(x, x) l n (5)} \frac{d}{d x} ((x, x) ln (5))

\frac{d}{d x} ((x, x) ln (5)) = ln (5) (, (1 \cdot x + 1 \cdot x))

= e^{(x, x) l n (5)} ln (5) (, (1 \cdot x + 1 \cdot x))

x^{5}

\int sin (t) 1 + cos (t) d t

9 e^{9 e^{x} + x}

\frac{d}{d x} (6 x + 6)

y^{^{''}} + 9 y = sec (3 x)

What is the derivative of 5^{x,x} ?
The derivative of 5^{x,x} is e^{(x,x)ln(5)}ln(5)(,(1*x+1*x))
What is the first derivative of 5^{x,x} ?
The first derivative of 5^{x,x} is e^{(x,x)ln(5)}ln(5)(,(1*x+1*x))