What is the solution for y^'=(cos^2(x))(cos^2(6y)) ?

The solution for y^'=(cos^2(x))(cos^2(6y)) is y=(arctan(3(x+1/2 sin(2x))+c_{1}))/6+(pin)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(cos^2(x))(cos^2(6y))

y^{^{'}} = (cos^{2} (x)) (cos^{2} (6 y))

y = \frac{arctan ( 3 ( x + \frac{1}{2} sin ( 2 x ) ) + c _{1} )}{6} + \frac{πn}{6}

Solution steps

y^{'} (x) = (cos^{2} (x)) (cos^{2} (6 y))

Solve separable ODE:

y = \frac{arctan ( 3 ( x + \frac{1}{2} sin ( 2 x ) ) + c _{1} )}{6} + \frac{πn}{6}

y = \frac{arctan ( 3 ( x + \frac{1}{2} sin ( 2 x ) ) + c _{1} )}{6} + \frac{πn}{6}

\frac{d y}{d x} = 7 y e^{x + 6}

\frac{( e ^{- 2 s} )}{s - 9}

f (x) = cos (a^{4} + x^{4})

\int cos (x) (sin^{2} (x)) d x

\int (sin (t))^{2} d t

What is the solution for y^'=(cos^2(x))(cos^2(6y)) ?
The solution for y^'=(cos^2(x))(cos^2(6y)) is y=(arctan(3(x+1/2 sin(2x))+c_{1}))/6+(pin)/6