What is the integral of 1/(x(x^2+5)) ?

The integral of 1/(x(x^2+5)) is 1/5 ln|x|-1/10 ln|x^2+5|+C

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integral of 1/(x(x^2+5))

\int \frac{1}{x ( x ^{2} + 5 )} d x

\frac{1}{5} ln ∣ x ∣ - \frac{1}{10} ln x^{2} + 5 + C

Solution steps

\int \frac{1}{x ( x ^{2} + 5 )} d x

Take the partial fraction of

\frac{1}{x ( x ^{2} + 5 )} : \frac{1}{5 x} - \frac{x}{5 ( x ^{2} + 5 )}

= \int \frac{1}{5 x} - \frac{x}{5 ( x ^{2} + 5 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{5 x} d x - \int \frac{x}{5 ( x ^{2} + 5 )} d x

\int \frac{1}{5 x} d x = \frac{1}{5} ln ∣ x ∣

\int \frac{x}{5 ( x ^{2} + 5 )} d x = \frac{1}{10} ln x^{2} + 5

= \frac{1}{5} ln ∣ x ∣ - \frac{1}{10} ln x^{2} + 5

Add a constant to the solution

= \frac{1}{5} ln ∣ x ∣ - \frac{1}{10} ln x^{2} + 5 + C

\int - e^{- k t} k M d t

\frac{\partial}{\partial x} (arctan (x y) - z)

x \to 0 lim (- 3 (- 6) + 3 (- 5))

y = x^{3} - 4 x, - 2 \leq x \leq 2

x \to 0 lim (\frac{x ^{2} + x}{x})

What is the integral of 1/(x(x^2+5)) ?
The integral of 1/(x(x^2+5)) is 1/5 ln|x|-1/10 ln|x^2+5|+C