What is area y=sin(x),y=sin(2x),x=0,x= pi/3 ?

The answer to area y=sin(x),y=sin(2x),x=0,x= pi/3 is 1/4

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area y=sin(x),y=sin(2x),x=0,x= pi/3

area

y = sin (x), y = sin (2 x), x = 0, x = \frac{π}{3}

\frac{1}{4}

Decimal Notation

0.25

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{3}} ∣ sin (x) - sin (2 x) ∣ d x

Solve

\int_{0}^{\frac{π}{3}} ∣ sin (x) - sin (2 x) ∣ d x : \frac{1}{4}

The area is:

= \frac{1}{4}

\frac{d}{d x} (1 - ln (cos (x)))

f (x) = \frac{x ^{2} - 4}{x - 3}

x \to - \infty lim (a^{x})

\int y^{2} ln (y) d y

\int \frac{x + 1}{x ^{2} - x + 1} d x

What is area y=sin(x),y=sin(2x),x=0,x= pi/3 ?
The answer to area y=sin(x),y=sin(2x),x=0,x= pi/3 is 1/4