What is the solution for xy^'+y=26sqrt(x) ?

The solution for xy^'+y=26sqrt(x) is y=(52x^{1/2})/3+(c_{1})/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xy^'+y=26sqrt(x)

x y^{^{'}} + y = 26 x

y = \frac{52 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

Solution steps

x y^{'} (x) + y = 26 x

Solve linear ODE:

y = \frac{52 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

y = \frac{52 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

y = 2 x^{3} - 6 x^{2} + 5 x + 1, (2, 3)

h^{^{'}} = - h

\frac{d}{d x} (\frac{4}{3})

\frac{d}{d x} (sin^{3} (x) cos (x))

(7 - 4) (73)

What is the solution for xy^'+y=26sqrt(x) ?
The solution for xy^'+y=26sqrt(x) is y=(52x^{1/2})/3+(c_{1})/x