What is the derivative of (1+3x)(6-5x) ?

The derivative of (1+3x)(6-5x) is -30x+13

What is the first derivative of (1+3x)(6-5x) ?

The first derivative of (1+3x)(6-5x) is -30x+13

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derivative of

(1 + 3 x) (6 - 5 x)

- 30 x + 13

Solution steps

\frac{d}{d x} ((1 + 3 x) (6 - 5 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 1 + 3 x, g = 6 - 5 x

= \frac{d}{d x} (1 + 3 x) (6 - 5 x) + \frac{d}{d x} (6 - 5 x) (1 + 3 x)

\frac{d}{d x} (1 + 3 x) = 3

\frac{d}{d x} (6 - 5 x) = - 5

= 3 (6 - 5 x) + (- 5) (1 + 3 x)

Simplify

3 (6 - 5 x) + (- 5) (1 + 3 x) : - 30 x + 13

= - 30 x + 13

y = \frac{10}{x ^{3}}

(4 x y^{2} + 4 y) d x + (4 x^{2} y + 4 x) d y = 0

a cos (t)

\int cos^{2} (x) \cdot sin (x) d x

\frac{\partial}{\partial x} (2 z^{10})

What is the derivative of (1+3x)(6-5x) ?
The derivative of (1+3x)(6-5x) is -30x+13
What is the first derivative of (1+3x)(6-5x) ?
The first derivative of (1+3x)(6-5x) is -30x+13