What is (\partial)/(\partial x)(e^{4xyz-9}) ?

The answer to (\partial)/(\partial x)(e^{4xyz-9}) is e^{4xyz-9}*4yz

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(\partial)/(\partial x)(e^{4xyz-9})

\frac{\partial}{\partial x} (e^{4 x yz - 9})

e^{4 x yz - 9} \cdot 4 yz

Solution steps

\frac{\partial}{\partial x} (e^{4 x yz - 9})

Treat

y, z

as constants

Apply the chain rule:

e^{4 x yz - 9} \frac{\partial}{\partial x} (4 x yz - 9)

= e^{4 x yz - 9} \frac{\partial}{\partial x} (4 x yz - 9)

\frac{\partial}{\partial x} (4 x yz - 9) = 4 yz

= e^{4 x yz - 9} \cdot 4 yz

\frac{2 x + 6 x ^{2}}{( 1 + 6 x ) ^{2}}

x^{3} + 3 x^{2} + x + 3

\int_{0}^{2} x^{3} - x d x

x^{3} + x^{2} - x - 3, at x = - 2

\int 7 x e^{- x} d x

What is (\partial)/(\partial x)(e^{4xyz-9}) ?
The answer to (\partial)/(\partial x)(e^{4xyz-9}) is e^{4xyz-9}*4yz