What is the integral of (4x+3)*(2x^2+3x)^3 ?

The integral of (4x+3)*(2x^2+3x)^3 is 4x^8+24x^7+54x^6+54x^5+(81x^4)/4+C

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integral of (4x+3)*(2x^2+3x)^3

\int (4 x + 3) \cdot (2 x^{2} + 3 x)^{3} d x

4 x^{8} + 24 x^{7} + 54 x^{6} + 54 x^{5} + \frac{81 x ^{4}}{4} + C

Solution steps

\int (4 x + 3) (2 x^{2} + 3 x)^{3} d x

Expand

(4 x + 3) (2 x^{2} + 3 x)^{3} : 32 x^{7} + 168 x^{6} + 324 x^{5} + 270 x^{4} + 81 x^{3}

= \int 32 x^{7} + 168 x^{6} + 324 x^{5} + 270 x^{4} + 81 x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 32 x^{7} d x + \int 168 x^{6} d x + \int 324 x^{5} d x + \int 270 x^{4} d x + \int 81 x^{3} d x

\int 32 x^{7} d x = 4 x^{8}

\int 168 x^{6} d x = 24 x^{7}

\int 324 x^{5} d x = 54 x^{6}

\int 270 x^{4} d x = 54 x^{5}

\int 81 x^{3} d x = \frac{81 x ^{4}}{4}

= 4 x^{8} + 24 x^{7} + 54 x^{6} + 54 x^{5} + \frac{81 x ^{4}}{4}

Add a constant to the solution

= 4 x^{8} + 24 x^{7} + 54 x^{6} + 54 x^{5} + \frac{81 x ^{4}}{4} + C

\int \frac{( x ^{3} )}{x ^{2} + 64} d x

\frac{d}{d x} ((3 x + 2) (x - 1)^{3})

y = x^{3} - 2 x + 1, (3, 22)

(- 3 x + 14)^{\frac{4}{3}}, 2

\frac{\partial}{\partial x} (x^{5} + x^{2} y + x + 1)

What is the integral of (4x+3)*(2x^2+3x)^3 ?
The integral of (4x+3)*(2x^2+3x)^3 is 4x^8+24x^7+54x^6+54x^5+(81x^4)/4+C